SOLUTION: My homework question states: Write the equation of the linear function whose graph contains the point (-2,4) and is perpendicular to the line whose equation is 2x+y=10.
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-> SOLUTION: My homework question states: Write the equation of the linear function whose graph contains the point (-2,4) and is perpendicular to the line whose equation is 2x+y=10.
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Question 371607: My homework question states: Write the equation of the linear function whose graph contains the point (-2,4) and is perpendicular to the line whose equation is 2x+y=10.
How do I solve this? Found 2 solutions by checkley77, mananth:Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! (-2,4) and is perpendicular to the line whose equation is
2x+y=10 ( red line).
Y=-2X+10 THIS LINE HAS A SLOPE=-2
THEREFORE A PERPENDICULAR LINE WILL HAVE A SLOPE=+1/2 (THE NEGATIVE RECIPRICAL)
Y=mX+b where m=slope & b=the y intercept.
Substitute the values of the X & Y points & solve for b.
4=1/2*-2+b
4=-1+b
b=4+1
b=5 Thus the equation is:
Y=X/2+5 (green line) (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions -2x +10 and x/2 +5).
You can put this solution on YOUR website! the given equation is 2x+y=10
re-write in slope intercept form
y=-2x+10
compare with equation
y = mx+b
slope m=-2
..
the desired line is perpendicular to this line so slope is negative reciprocal of the given line
slope = 1/2
..
passing through (-2,4)
y= mx+b
plug value of m x,y
4=1/2*-2+b
4=-1+b
b=5
so the line will be y = (1/2)x+5
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