SOLUTION: This is a practice question that I have and I am completely stuck...
A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of intere
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A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of intere
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Question 371596: This is a practice question that I have and I am completely stuck...
A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of interest from both investments is $91. How much is invested at 8%.
Here is all that I have
91 = (x)(.1)(1) + (y)(.08)(2)
910 = x + .16y
I am not sure where to go from here and to be honest, I am not even sure if I am on the right track... Please Help ... Thank You
You can put this solution on YOUR website! .10x+.08*2x=91
.10x+.16x=91
.26x=91
x=91/.26
x=350 invested @ 10%.
2*350=700 invested @ 8%
Proof:
.10*350+.08*700=91
35+56=91
91=91
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