SOLUTION: solve this equation: 42b^9-2b^7+48b^3 divided by 6b^3-24b^7

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Question 371391: solve this equation: 42b^9-2b^7+48b^3 divided by 6b^3-24b^7
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
%2842b%5E9-2b%5E7%2B48b%5E3%29%2F%286b%5E3-24b%5E7%29
First we factor out the Greatest Common Factor (GCF). The GCF in the numerator is 2b%5E3 and in the denominator it is 6b%5E3:
%282b%5E3%2821b%5E6-b%5E4%2B24%29%29%2F%286b%5E3%281-4b%5E4%29%29
The second factor of the numerator will not factor. So even though the second factor in the denominator is a difference of squares and will factor, there is no point because neither of those factors will cancel with a factor in the numerator. All we can do now is factor the 6:
%282b%5E3%2821b%5E6-b%5E4%2B24%29%29%2F%282%2A3%2Ab%5E3%281-4b%5E4%29%29
Now we can cancel:

leaving:
%2821b%5E6-b%5E4%2B24%29%2F%283%2A%281-4b%5E4%29%29
or
%2821b%5E6-b%5E4%2B24%29%2F%283-12b%5E4%29%29