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The three logarithms in the parentheses are not like terms so we cannot subtract them. However there is a property of logarithms, , which allows us to combine two logarithms into one if all of the following are true:
There is a mimus between them.
The bases of the logarithms are the same.
The coefficient of each logarithm is a 1.
Your logarithms meet the first two requirements. But the first logarithm has a coefficient of 2. Fortunately there is another property of logarithms, , which allows us to "move" a coefficient into the argument as an exponent. So we start by using this property on the first logarithm:
Now we can use the first property on the first two logarithms:
Next we can use the first property again to combine the remaining logarithms:
which simplifies to:
This may be condensed enough. But we can use the second property again to move the coefficient of 1/3:
This may be the desired answer. Alternatively, since 1/3 as an exponent means "cube root", we could rewrite this as:
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