SOLUTION: 3log (base 2) (5x)= 12 X=???

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Question 37121: 3log (base 2) (5x)= 12
X=???
Found 2 solutions by AnlytcPhil, longjonsilver:
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!


                            3·log2(5x) = 12

Divide both sides by 3

                              log2(5x) = 4

Use the fact that equation

    logBA = C 

is equivalent to the equation 

       A = BC

                                   5x = 24

                                   5x = 2·2·2·2

                                   5x = 16

                                    x = 16/5 

     
Edwin McCravy
AnlytcPhil@aol.com

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
ignoreing the words base2 for sake of clarity:

+3log%285x%29=+12+
+log%285x%29=+4+

So, to reverse log-base2 we need to raise both sides as follows:
+2%5E%28log%285x%29%29+=+2%5E4+
+5x+=+16+
+x+=+16%2F5+

jon.