SOLUTION: How do i solve 300 + 10x is greater than or equal too 20x - 600?
And
How do i solve -25x + 50 < 75x - 1150 ?
Please help, i do not understand
Algebra ->
Inequalities
-> SOLUTION: How do i solve 300 + 10x is greater than or equal too 20x - 600?
And
How do i solve -25x + 50 < 75x - 1150 ?
Please help, i do not understand
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Question 371127: How do i solve 300 + 10x is greater than or equal too 20x - 600?
And
How do i solve -25x + 50 < 75x - 1150 ?
Please help, i do not understand Found 2 solutions by Fombitz, rfer:Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! How would you solve it if it was ??
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The rules are all the same except for one rule.
If you multiply or divide by a negative value, change the direction of the inequality.
I'll do the first one, you do the next. <--- Subtract 20x from both sides <--- Subtract 300 from both sides. <--- Divide by -10, Change the direction of the inequality
You can put this solution on YOUR website! 300+10x > 2x-600
work the problem just as if it had an = instead of >
8x > -900
x > -112.5
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-25x+50 < 75x-1150
1200 < 100x
12 < x