SOLUTION: This question has been bothering me for quite a while now.
4 x 5^(X+2) = 5 x 4^(2X)
(big 'X' is the variable, solve for X)
I tried taking the log of both sides to get
l
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: This question has been bothering me for quite a while now.
4 x 5^(X+2) = 5 x 4^(2X)
(big 'X' is the variable, solve for X)
I tried taking the log of both sides to get
l
Log On
Question 37055: This question has been bothering me for quite a while now.
4 x 5^(X+2) = 5 x 4^(2X)
(big 'X' is the variable, solve for X)
I tried taking the log of both sides to get
log 4 + (X+2)log 5 = log 5 + (2X)log 4
then group like terms
(X+2)log 5 - (2X)log 4 = log 5 - log 4
then I get stuck...
any help? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 4 x 5^(X+2) = 5 x 4^(2X)
Take the log of both sides to get:
log4+(x+2)log5 = log5+(2x)log4
log4+xlog5+2log5= log5+(2x)log4
x(log5-2log4)=-(log5+log4)
x(-0.50514998)=-1.30103000
x= -2.57553211
Cheers,
stan H.
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