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Question 370491: A woodworking shop makes tables and chairs. To make a chair, 8 min is needed on the lathe and 8 min is needed on the sander. To make a table, 8 min is needed on the lathe and 20 min is needed on the sander. The lather operator works 6h/day and the sander operator works 7h/day. How many chairs and tables can they make in one day working at this capacity?
I'm having difficulty setting up the two equations for this question. I'm required to set up equations and solve them using either substitution method or elimination method.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A woodworking shop makes tables and chairs.
To make a chair, 8 min is needed on the lathe and 8 min is needed on the sander.
To make a table, 8 min is needed on the lathe and 20 min is needed on the sander.
The lather operator works 6h/day and the sander operator works 7h/day.
How many chairs and tables can they make in one day working at this capacity?
:
Let c = no. of chairs
Let t = no. of tables
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Change the hrs to minutes, 6 hr = 360 min; 7 hrs = 420 min
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The lathe equation
8c + 8t = 360
the sander equation
8c + 20t = 420
:
You can use elimination
8c + 20t = 420
8c + 8t = 360
----------------subtraction eliminates c find t
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