SOLUTION: $9500 is invested, part of it at 10% and part of it at 8%. For a certain year, the total yield is $878.00. How much was invested at each rate? How much was invested at 10%? How

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: $9500 is invested, part of it at 10% and part of it at 8%. For a certain year, the total yield is $878.00. How much was invested at each rate? How much was invested at 10%? How      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 370476: $9500 is invested, part of it at 10% and part of it at 8%. For a certain year, the total yield is $878.00. How much was invested at each rate?
How much was invested at 10%?
How much was invested at 8%?
thank you

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
0.10x + 0.08(9500 - x) = 878,
0.10x + 760 - 0.08x = 878,
0.02x = 118,
x = 5900, the amount invested in the 10%, and 9500-5900 = 3600, invested in the 8%.