SOLUTION: Systems with three variables. Solve 3x+2y-z=1 x-2y+z=0 2x+y-3z=-1

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Question 370453: Systems with three variables.

Solve
3x+2y-z=1
x-2y+z=0
2x+y-3z=-1
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
3x + 2y -  z =  1
 x - 2y +  z =  0
2x +  y - 3z = -1

There are many ways to solve it.  
The solution is x=1%2F4, y=9%2F20, z=13%2F20

If you want to know how to solved one of the many ways, 
please state which way you are studying.  Substitution,
elimination, Cramer's rule, augmented matrix, or the AX=B 
matrix method using the inverse.  

Edwin