SOLUTION: find two consecutive odd integers such that five times the first integer is 25 less than twice the greater integer

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Question 370382: find two consecutive odd integers such that five times the first integer is 25 less than twice the greater integer
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find two consecutive odd integers such that five times the first integer is 25 less than twice the greater integer
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1st: 2x-1
2nd: 2x+1
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Equation:
5(2x-1) = 2(2x+1)-25
10x-5 = 4x+2-25
6x = -18
x = -3
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1st: 2x-1 = -7
2nd: 2x+1 = -5
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Cheers,
Stan H.
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Let x represent the smaller of the two consecutive odd integers.

the other then would be (x+2)

Write as we Read

5x = 2(x+2) - 25

solving for x

5x = 2x + 4 - 25

3x = -21

x = -7, the smaller consecutive odd integers. The larger is -5  (-7+2)

Checking our answer

5*-7 = 2*-5 - 25 = 35