SOLUTION: How do you graph the following: x+3=-1/24(y-2)^2 y+2=-1/24(x-3)^2 x-3=-1/24(y+2)^2 x-3= 1/24(y+2)^2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: How do you graph the following: x+3=-1/24(y-2)^2 y+2=-1/24(x-3)^2 x-3=-1/24(y+2)^2 x-3= 1/24(y+2)^2      Log On


   

Question 370297: How do you graph the following:
x+3=-1/24(y-2)^2
y+2=-1/24(x-3)^2
x-3=-1/24(y+2)^2
x-3= 1/24(y+2)^2
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
See Problem 370308