SOLUTION: find the vertex the line of symmetry the maximum and minimum value of the quadratic function. F(x)=x^2-12x-3

Algebra ->  Rational-functions -> SOLUTION: find the vertex the line of symmetry the maximum and minimum value of the quadratic function. F(x)=x^2-12x-3      Log On


   

Question 370262: find the vertex the line of symmetry the maximum and minimum value of the quadratic function. F(x)=x^2-12x-3
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square to put the equation into vertex form,y=a%28x-h%29%5E2%2Bk
f%28x%29=x%5E2-12x-3
f%28x%29=%28x%5E2-12x%2B36%29-3-36
f%28x%29=%28x-2%29%5E2-39
The vertex is (2,-39).
The vertex lies on the axis of symmetry x=2
Since a=1%3E0 then the parabola opens upwards and the value at the vertex is the function minimum.
y%5Bmin%5D=-39