SOLUTION: If 8/3 of a cetain number is subtracted from eight times the number the result is 128. Find the number.
One number is 20 more than a second number. Their sum is twenty six. What
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-> SOLUTION: If 8/3 of a cetain number is subtracted from eight times the number the result is 128. Find the number.
One number is 20 more than a second number. Their sum is twenty six. What
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Question 370233: If 8/3 of a cetain number is subtracted from eight times the number the result is 128. Find the number.
One number is 20 more than a second number. Their sum is twenty six. What are the numbers?
If tem times the smaller of two consectuve integers is added to six times the larger, the result is 118. Find the integers.
Please help me write all three of them in equation form. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! If 8/3 of a cetain number is subtracted from eight times the number the result is 128. Find the number.
8x - (8/3)x]= 128
One number is 20 more than a second number. Their sum is twenty six. What are the numbers?
lets second number be x
first number = x+20
x+x+20=26
2x+20 =26
If tem times the smaller of two consectuve integers is added to six times the larger, the result is 118. Find the integers.
..
x, x+1 be the integers
10 times smaller = 10x
6 times larger = =6(x+1)
10x+6(x+1)= 110
