SOLUTION: The real zeros (arranged in increasing order ) of the polynomial
P(x)=x^4-3x^3-11x^2+25x+12 are given by
x1_________ x2___________ x3___________ x4___________
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-> SOLUTION: The real zeros (arranged in increasing order ) of the polynomial
P(x)=x^4-3x^3-11x^2+25x+12 are given by
x1_________ x2___________ x3___________ x4___________
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Question 370224: The real zeros (arranged in increasing order ) of the polynomial
P(x)=x^4-3x^3-11x^2+25x+12 are given by
x1_________ x2___________ x3____________ x4____________ Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The real zeros (arranged in increasing order ) of the polynomial
P(x)=x^4-3x^3-11x^2+25x+12 are given by
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I graphed it and found solid zeroes at x = -3 and at x = 4.
Using those and synthetic division solve the resulting quadratic
quotient:
-3)....1....-3....-11....25....12
........1.....-6....7.....4....|..0
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4)....1....-6....7....4
.......1.....-2...-1...|..0
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Quotient: x^2-2x-1
Quadratic Formula:
x = [2+-sqrt(4-4*-1)]/2
x = [2+-2sqrt(2)]/2
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x1 = -3______ x2 = 1-sqrt(2)_______ x3 = 1+sqrt(2)_______ x4 = 4____________
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Cheers,
Stan H.
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