You can put this solution on YOUR website! 2+3i 7-2i
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3-2i 8+i
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Step 1, get the i's out of the denominators. Multiply NUM and DEN by the conjugate of the DEN
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(2+3i)*(3+2i) (7-2i)*(8-i)
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(3-2i)*(3+2i) (8+i)*(8-i)
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(6+13i-6) (56 - 23i - 2)
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(9 + 4) (64 + 1)
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13i (54 - 23i)
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13 65
= (54 - 23i)/65 + i
= (54 - 23i)/65 + 65i/65
= (54 + 42i)/65