SOLUTION: Using the power law solve the folowing to the nearest hundredth. {{{ 2^(x+2) = 5^(x-1) }}} I can get the problem so far and then I get confused as to what I should do next.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Using the power law solve the folowing to the nearest hundredth. {{{ 2^(x+2) = 5^(x-1) }}} I can get the problem so far and then I get confused as to what I should do next.       Log On


   



Question 369671: Using the power law solve the folowing to the nearest hundredth.
+2%5E%28x%2B2%29+=+5%5E%28x-1%29+
I can get the problem so far and then I get confused as to what I should do next.
+log2%5E%28x%2B2%29+=+log5%5E%28x-1%29+
(x+2)log2 = (x-1)log5
xlog2 + 2log2 = xlog5 - log5
xlog2 -xlog5 = -log5 - 2log2
x(log2/5) =
And now I am stuck, if anyone could help me wth what to do next, it would be greatly appreciated.
Thanks

Answer by Fombitz(32388) About Me  (Show Source):