SOLUTION: find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 82

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Question 369645: find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 82
Found 2 solutions by Fombitz, checkley77:
Answer by Fombitz(32388) About Me  (Show Source):
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N, N%2B2, and N%2B4 are the integers.
.
.
N%2B2%28N%2B2%29%2B3%28N%2B4%29=82
N%2B2N%2B4%2B3N%2B12=82
6N%2B16=82
6N=66
N=11
The integers are 11, 13 and 15.

Answer by checkley77(12844) About Me  (Show Source):
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Let x, x+2 & x+4 be the 3 integers.
x+2(x+2)+3(x+4)=82
x+2x+4+3x+12=82
6x=82-4-12
6x=66
x=66/6
x=11 ans. for the first innteger.
11+2=13 ans. for the second integer.
11+4=15 ans. for the third integer.
Proof:
11+2*13+3*15=82
11+26+45=82
82=82