SOLUTION: Julissa can unload a ship’s cargo twice as fast as Chris. Together, they can unload the cargo in 4 hours. How long would it take each of them working alone to unload the cargo?

Algebra ->  Functions -> SOLUTION: Julissa can unload a ship’s cargo twice as fast as Chris. Together, they can unload the cargo in 4 hours. How long would it take each of them working alone to unload the cargo?       Log On


   

Question 369564: Julissa can unload a ship’s cargo twice as fast as Chris. Together, they can unload the cargo in 4 hours. How long would it take each of them working alone to unload the cargo?
Found 2 solutions by ewatrrr, jrfrunner:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Let x represent the amount of time it would take Julissa.  Then the time it takes Chris would be 2x

Per hour is the Equalizer***

1/x + 1/2x = 1/4hr 

Mulitplying each term on both sides of the equation by 4x so as all denominators = 1

4 + 2 = x

6hr = x , the time takes Julissa alone.  Chris's time alone would be 12hr

checking our answer

1/6 + 1/12 = 2/12 + 1/12 = 3/12 = 1/4

Answer by jrfrunner(365) About Me  (Show Source):
You can put this solution on YOUR website!
Let C= Chris' Time
Let J=Julissa's Time = 1/2C
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working together,each hour they complete 1/c+1/(0.5C) of the unloading. And each hour equates to 1/4 of the unlaoding.
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1/c+1/(.5C)=1/4
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1/c+2/c=1/4
3/c=1/4
c=12 by cross multiplying.
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Therefore Chris takes 12 hours alone, and since J=1/2C=6 hours for Julissa