SOLUTION: Three brothers have ages that are consecutive odd integers. The difference between the age of the oldest and twice the age of the youngest is twenty-four less than the middle broth

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Question 369533: Three brothers have ages that are consecutive odd integers. The difference between the age of the oldest and twice the age of the youngest is twenty-four less than the middle brother’s age. Find their ages.
Answer by Fombitz(32388) About Me  (Show Source):
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N, N%2B2, and N%2B4 are the ages.
%28N%2B4%29-%282N%29=%28N%2B2%29-24
4-N=N-22
2N=26
N=13
The brothers are 13, 15, and 17 years old.