SOLUTION: how to factor 2x^3-3x^2-11x+6?

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Question 369470: how to factor 2x^3-3x^2-11x+6?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Graph it to look for zeros.
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graph%28300%2C300%2C-4%2C4%2C-4%2C4%2C0%2C2x%5E3-3x%5E2-11x%2B6%29
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Looks like x=-2, x=3, and x=1%2F2 are zeros of the function.
Verify by plugging those values into the equation and getting a zero.
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2x%5E3-3x%5E2-11x%2B6=2%28-2%29%5E3-3%28-2%29%5E2-11%28-2%29%2B6
2x%5E3-3x%5E2-11x%2B6=2%283%29%5E3-3%283%29%5E2-11%283%29%2B6
2x%5E3-3x%5E2-11x%2B6=2%281%2F2%29%5E3-3%281%2F2%29%5E2-11%281%2F2%29%2B6
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If so then x%2B2, x-3, and x-1%2F2 are factors of the polynomials.