Question 369450: 8 years ago, Jimmy was 3 times as old as Anne. In 4 years, Jimmy will be 3/2 of Anne's age. What is each ages?
Answer by amoresroy(361)   (Show Source):
You can put this solution on YOUR website! 8 years ago, Jimmy was 3 times as old as Anne. In 4 years, Jimmy will be 3/2 of Anne's age. What is each ages?
Let J = age of Jimmy
A = age of Anne
1st equation
J- 8 = 3(A -8)
J- 8 = 3A -24
J-3A = -16
2nd equation
J + 4 = 3/2(A+4)
J + 4 = 1.5A + 6
J - 1.5A = 2
Deduct the 1st equation from the 2nd equation
(J-J) -1.5-(-3A) = 2-(-16)
1.5A = 18
A = 12
Substitute The value of A in equation1 to solve for J
J - 3(12) = -16
J = 36-16
J = 20
Anne is 12 years old and Jimmy is 20 years old.
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