SOLUTION: Three times one number minus a second is 8, and the sum of the numbers is 12. Find the numbers.

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Question 369177: Three times one number minus a second is 8, and the sum of the numbers is 12. Find the numbers.
Answer by lefty4ever26(59) About Me  (Show Source):
You can put this solution on YOUR website!
3 times one number (3x) minus a second (-y) is 8 (=8). SO 3x-y=8.
sum of numbers (x+y) is 12 (=12). SO x+y=12.
3x-y=8
x%2By=12 Solve this equation for y to get y=12-x Then you will plug this new value of y into the first equation and solve for x.
3x-%2812-x%29=8
3x-12%2Bx=8
4x-12=8
4x=20
x=5 Then plug this value for x back into one of the equations to find y.
x%2By=12
%285%29%2By=12
y=7
So the two numbers are 5 and 7.