SOLUTION: Find 4 consecutive odd integers such that the sum of the first and fourth is 75 more than 3 times the third.

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Question 369163: Find 4 consecutive odd integers such that the sum of the first and fourth is 75 more than 3 times the third.
Answer by lefty4ever26(59) About Me  (Show Source):
You can put this solution on YOUR website!
FIND 4 CONSECUTIVE ODD INTEGERS
The first integer is x, the second is x+2, the third is x+4, the fourth is x+6.
The sum of the first and fourth (x+(x+6))
=75 more than 3 times the third (75+3(x+4)
SO (x+x+6)=75+3(x+4) Solve for x.
2x%2B6=3x%2B87
6=x%2B87
x=-81 So plugging this value in for x in the formulas for each integer.
x=-81
x+2=(-81)+2=-79
x+4=(-81)+4=-77
x+6=(-81)+6=-75
So your 4 integers are -81, -79, -77, -75