SOLUTION: I have 16^(3/2)=64 and i have to put it in log form. I got the answer as log(base16)64=3/2. But it does not check, what am i doing wrong?

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I have 16^(3/2)=64 and i have to put it in log form. I got the answer as log(base16)64=3/2. But it does not check, what am i doing wrong?      Log On


   

Question 369027: I have 16^(3/2)=64 and i have to put it in log form. I got the answer as log(base16)64=3/2. But it does not check, what am i doing wrong?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
If you started with:
+16%5E%283%2F2%29=64+
taking log base 16 of both sides:
+3%2F2+=+log%2816%2C64%29+
+3%2F2+=+log%2864%29%2Flog%2816%29+
cross multiplying
+3%2Alog%2816%29+=+2%2Alog%2864%29+
...
easier way would be to:
+16%5E%283%2F2%29=64+
+sqrt%2816%5E3%29=64+
+sqrt%2816%2A16%2A16%29=64+
+16%2Asqrt%2816%29=64+
+16%2Asqrt%284%2A4%29=64+
+16%2A4=64+
+64=64+