Question 368862: Find three consecutive odd integers such that the sum of the smallest and 4 times the largest is 61.
I hate to ask someone to help, but i've been stuck on this for maybe an hour or 2 and i just cant understand itt! I know the answers are 9, 11, and 13, but thats only cause some kid told me. But i cant figure out how to get it! I would aprpriciate any help at all. (:
Answer by neatmath(302)   (Show Source):
You can put this solution on YOUR website! Let x be the first odd integer.
Then the next two consecutive odd integers are x+2 and x+4
Then we are given:
the sum of the smallest and 4 times the largest is 61 or
x+4*(x+4)=61
x+4x+16=61
5x=45
x=9
Thus the three consecutive odd integers are 9, 11, and 13 as you already knew.
If you check the rest of my answers here on algebra.com you can see a couple more examples of this that I just recently solved.
If you are still having problems, send me an email!
I hope this helps!
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