Question 368840: 2x+4y=-10;(4,2)
write equation of a line that is perpendicular to the given line and that passes through the given point Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! 2x+4y=-10;(4,2)
...
2x+4y=-10
/2
x+2y=5
-x
2y+x-x=-x+5
2y=-x+5
/2
y=(-1/2)x+5/2
slope = (-1/2)
..
the slope perpendicular to this line will have a negative reciprocal as slope
=2
..
The new line passes through ;(4,2)
...
equation of line = (y-4)=2(x-2)
y-4=2x-4
y=2x
...
...
m.ananth@hotmail.ca