Question 368743: 4x-12y=2;(10,-1)
write the equation of a line that is perpendicular to the given line and that passes through the given point Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! 4x-12y=2
12y=4x-2
/12
y= (1/3)X -1/6
slope = 1/3
..
the line perpendicular will have a slope of -3
equation of line passing through (10,-1) & slope -3
(y-10)=-3(x+1)
y-10 = -3x-3
y=-3x+7
...
...
m.ananth@hotmail.ca