SOLUTION: m/m^2-m-12 + 5/m+3
This is what i came up with but i'm not exactly sure how i got it. I'm not sure how to get the denominators the same. Please walk me through this proble
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Rational-functions
-> SOLUTION: m/m^2-m-12 + 5/m+3
This is what i came up with but i'm not exactly sure how i got it. I'm not sure how to get the denominators the same. Please walk me through this proble
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Question 36872: m/m^2-m-12 + 5/m+3
This is what i came up with but i'm not exactly sure how i got it. I'm not sure how to get the denominators the same. Please walk me through this problem step by step. Thank you. I don't have a text book. My instructor gives us problems from his book.
5(m-4)/m+3(m+3)(m-4)
m+5m-20
answer =
6m-20/m^2-m-12 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! m/m^2-m-12 + 5/m+3
=m/[(m-4)(m+3)] + 5/(m+3)
The LCD = (m-4)(m+3)
Rewrite each fraction with this LCD is its denominator, as follows:
= m/LCD + 5(m-4)/LCD
Now add the fractions to get:
=[m+5(m-4)]/LCD
Simplify as much as possible, as follows:
=[6m-20]/[(m-4)(m+3)]
Your answer is correct.
Cheers,
Stan H.
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