SOLUTION: 5c^2-17c+14

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Question 368669: 5c^2-17c+14
Answer by jim_thompson5910(35256) About Me  (Show Source):
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I'm assuming that you want to factor this right? Please post the full instructions.



Looking at 5c%5E2-17c%2B14 we can see that the first term is 5c%5E2 and the last term is 14 where the coefficients are 5 and 14 respectively.

Now multiply the first coefficient 5 and the last coefficient 14 to get 70. Now what two numbers multiply to 70 and add to the middle coefficient -17? Let's list all of the factors of 70:



Factors of 70:
1,2,5,7,10,14,35,70

-1,-2,-5,-7,-10,-14,-35,-70 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 70
1*70
2*35
5*14
7*10
(-1)*(-70)
(-2)*(-35)
(-5)*(-14)
(-7)*(-10)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to -17? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -17

First NumberSecond NumberSum
1701+70=71
2352+35=37
5145+14=19
7107+10=17
-1-70-1+(-70)=-71
-2-35-2+(-35)=-37
-5-14-5+(-14)=-19
-7-10-7+(-10)=-17



From this list we can see that -7 and -10 add up to -17 and multiply to 70


Now looking at the expression 5c%5E2-17c%2B14, replace -17c with -7c%2B-10c (notice -7c%2B-10c adds up to -17c. So it is equivalent to -17c)

5c%5E2%2Bhighlight%28-7c%2B-10c%29%2B14


Now let's factor 5c%5E2-7c-10c%2B14 by grouping:


%285c%5E2-7c%29%2B%28-10c%2B14%29 Group like terms


c%285c-7%29-2%285c-7%29 Factor out the GCF of c out of the first group. Factor out the GCF of -2 out of the second group


%28c-2%29%285c-7%29 Since we have a common term of 5c-7, we can combine like terms

So 5c%5E2-7c-10c%2B14 factors to %28c-2%29%285c-7%29


So this also means that 5c%5E2-17c%2B14 factors to %28c-2%29%285c-7%29 (since 5c%5E2-17c%2B14 is equivalent to 5c%5E2-7c-10c%2B14)



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Answer:
So 5c%5E2-17c%2B14 factors to %28c-2%29%285c-7%29