You can put this solution on YOUR website! the sum of the squares of two consecutive integers is 265. find the integers.
Let the smaller number be "x"
The larger is "x+1"
EQUATION:
x^2 + (x+1)^2=265
2x^2+2x+1=265
2x^2+2x-264=0
x^2+x-132=0
(x+12)(x-11)=0
x=11 then x+1=12
If x=-12 the x+1=-11
Cheers,
Stan H.