SOLUTION: A man passed one sixth of his life in childhood, one twelfth in youth, and one seven more as a bachelor. Five years after his marriage, a son was born who died four years before hi

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Question 368114: A man passed one sixth of his life in childhood, one twelfth in youth, and one seven more as a bachelor. Five years after his marriage, a son was born who died four years before his father at half his father's final age. What was the man's final age?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Let M= man's final age. Then
M%2F6+%2BM%2F12+%2B+M%2F7+%2B+5%2BM%2F2+%2B+4+=+M. Multiply both sides by 84, the LCD.
14M%2B7M+%2B+12M+%2B+420+%2B+42M%2B336+=+84M,
75M+%2B+756+=+84M,
756+=+9M,
M = 84, the man's final age.