SOLUTION: The sum of two numbers is 48 and their difference is 80. Find each ofthe number?
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Question 368035
:
The sum of two numbers is 48 and their difference is 80. Find each ofthe number?
Answer by
checkley77(12844)
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X+Y=48 or X=48-Y
X-Y=80
(48-Y)-Y=80
48-2Y=80
-2Y=80-48
-2Y=32
Y=32/-2
Y=-16 ANS.
X+(-16)=48
X-16=48
X=48+16
X=64 ANS.
PROOF:
64-(-16)=80
64+16=80
80=80