SOLUTION: 108y^9 + 4y^3
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Question 367984
:
108y^9 + 4y^3
Answer by
nyc_function(2741)
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I assume that you would like to factor.
Divide both terms by 4y^3 to factor.
108y^9 divided by 4y^3 = 27y^6.
4y^3 divided by 4y^3 = 1.
Final Answer: 4y^3(27y^6 + 1).