SOLUTION: find three consecutive odd integers such that three times the first is 9 greater than six times the third

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Question 367893: find three consecutive odd integers such that three times the first is 9 greater than six times the third
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Let x represent the smallest of the three consecutive odd integers.

The next two consecutive odd integers would be (x+2) and (x+4)

Write as we Read***

3x = 6(x+4) + 9

solve for x

3x = 6x + 24 + 9

-33 = 3x

-11 =x

the three consecutive odd integers are -11, -9 and -7

checking our answer

3*-11 = -33 = 6*-7 + 9