SOLUTION: Consecutive problem: Two times the first of three consecutive even integers less three times the second equals 4. Form an equation and solve it to find the three numbers. Th

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Question 367645: Consecutive problem:
Two times the first of three consecutive even integers less three times the second equals 4. Form an equation and solve it to find the three numbers.
This what I have:
2x+x+x+1-3=4
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x, x%2B2, and x%2B4 would be three consecutive even integers.
2x-3%28x%2B2%29=4
2x-3x-6=4
Now solve for x.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

Yes! Letting x represent the first of the three consecutive even integers.

***consecutive even integers differ by 2.  

the three consecutive even integers would be x,  (x+2) and (x+4)

Write as we Read***

2x - 3(x+2)= 4

solve for x

-x - 6 = 4

-10 = x

-10,-8 and -6 would be the three consecutive even integers



checking our answer

-20 - 3*-8 = -20 + 24 = 4