SOLUTION: Consider the equation x2 – 4x + 29 = 0.
(a) Compute the discriminant, b2 – 4ac and state whether there is one real-number solution, or two different real-number soluti
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-> SOLUTION: Consider the equation x2 – 4x + 29 = 0.
(a) Compute the discriminant, b2 – 4ac and state whether there is one real-number solution, or two different real-number soluti
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Question 367602: Consider the equation x2 – 4x + 29 = 0.
(a) Compute the discriminant, b2 – 4ac and state whether there is one real-number solution, or two different real-number solutions, or two different imaginary-number solutions.
(b) Use the quadratic formula to find the exact solutions of the equation. Show work.
You can put this solution on YOUR website! x2 – 4x + 29 = 0.
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a=1, b = -4, c= 29
b^2-4ac= 16-116
b^2-4ac=-100
it is less than 0
so the roots are complex
...
x1=
x1=2+5i
x2=
...
x2=2-5i
...
m.ananth@hotmail.ca
