|  | 
| 
 
 
| Question 367559:  The sum of two numbers is 133. Four times the smaller of the two numbers equals three times the greater number. Find the numbers. When (x) is the smaller number and (x+1) is the greater number.
 Found 2 solutions by  dudeantariksh, KaitieB:
 Answer by dudeantariksh(10)
      (Show Source): 
You can put this solution on YOUR website! hi there! well,
 we are given that the numbers are x and x+1.
 we are also old that their sum equals to 133.
 using this condition we can get the equation that
 x + (x+1) = 133
 therefore,
 x+x+1     = 133
 therefore,
 2x+ 1     = 133
 therefore,
 2x        = 133-1
 therefore,
 2x        = 132
 therefore.
 x         = 132/2
 therefore,
 x= 66
 therefore,
 x+1= 66+1
 that is,
 x+1= 67
 thereforre the two numbers are 67
 note- this numerical can be solved by using the track of linar equations in two variables, that is greater number as x and smaller one as y as we are given two conditions.
 but since we are given that the greater number is x+1 and the smaller number is x, we have chosen this way, of using a single x variable. thus, the sum can be accomplished even with a single condition. if any further clarification is required u're welcme
 
Answer by KaitieB(1)
      (Show Source): 
You can put this solution on YOUR website! x+(x+1)=133 x+x+1=133
 2x+1=133
 __-1__-1_
 2x  =132
 2x/2=132/2
 x   =66
 
 x+1=
 66+1=67
 Therefore the smaller number is 66 and the greater 67.
 | 
  
 | 
 |  |  |