SOLUTION: Find four consecutive integers such that eight times the sum of two and the smallest is equal to the sum of the smallest and twice the largest.

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Question 367398: Find four consecutive integers such that eight times the sum of two and the smallest is equal to the sum of the smallest and twice the largest.
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
x, x+1, x+2, x+3
8(2+x) = x+2(x+3),
16+8x = x+2x+6,
16+8x = 3x+6,
5x = -10,
x = -2,
the inetgers are -2,-1,0,1.