SOLUTION: Jack usually mos his lawn in 7 hours. Marilyn can mow the same yard in 5 hours. How much time would it take for them to mow the lawn together?
They could mow the lawn in ____
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Jack usually mos his lawn in 7 hours. Marilyn can mow the same yard in 5 hours. How much time would it take for them to mow the lawn together?
They could mow the lawn in ____
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Question 367243: Jack usually mos his lawn in 7 hours. Marilyn can mow the same yard in 5 hours. How much time would it take for them to mow the lawn together?
They could mow the lawn in ____ hours if they worked together.
i got 35/12 but the answer is looking for how many hours Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Jack usually mos his lawn in 7 hours. Marilyn can mow the same yard in 5 hours. How much time would it take for them to mow the lawn together?
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Jack rate = 1/7 job/hr
Marilyn rate = 1/5 job/hr
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Together rate = 1/x job/hr
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Equation:
rate + rate = together rate
1/7 + 1/5 = 1/x
5x + 7x = 35
12x = 35
x = 35/12 = 2 hrs + (11/12)60 min = 2 hrs 55 minutes (together time)
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Cheers,
Stan H.
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