Question 36694: Simplify [square root 32x^5y^2] / [square root 2x^3y^3]
I've tried getting the square root of 32 times square root of 5 times square root of y2 which went to 4 square of 2 x^4 y. The second part is square root of 2 times square of x^3 times Square root of y^3 But I think I'm going wrong with this.. Any help is appreciated
Answer by ilana(307)   (Show Source):
You can put this solution on YOUR website! sqrtx/sqrty=sqrt(x/y), so we can simplify the problem as sqrt(32x^5y^2/2x^3y^3), so we get sqrt(16x^2/y) = 4*(absolute value of x)/sqrty. But x must be non-negative because 32x^5y^2 is non-negative, so we get 4x/sqrt(y).
Your method of splitting each term works also, it's just a bit longer and more confusing.
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