SOLUTION: A freight train left a station at 12 noon going north at a rate of 50 miles per hour. At 1 p.m., a passenger train left the same station going south at the rate of 60 mph. At what

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A freight train left a station at 12 noon going north at a rate of 50 miles per hour. At 1 p.m., a passenger train left the same station going south at the rate of 60 mph. At what       Log On

Hi, 

Let x represent the time the train leaving at noon traveled

d= rt

50mph*x + 60mph*(x-1)=270

110x = 330

x = 3 hrs



checking our answer

50*3 + 60*2 = 150 + 120 = 270mi