SOLUTION: The length of a rectangle is 9 feet more than its width. The perimeter is 58 feet. find the dimensions.(prior knowledge: perimeter=2 times the length plus 2 times the width) How do

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The length of a rectangle is 9 feet more than its width. The perimeter is 58 feet. find the dimensions.(prior knowledge: perimeter=2 times the length plus 2 times the width) How do      Log On

Hi, 

Let x represent the width, then the length would be (x+9ft)

2(x+9ft) + 2*x = 58ft



Or

x = 10ft, the width.  the length = 19

2*10ft + 2*19ft = 20ft + 38ft = 58ft