Question 366853: I am given a table that states:
TIme in Minutes Tub Has Been Draining, X: (3 then 5) Depth in Water in Tub in Inches, Y: (18 then 12)
The question is:
How deep was the water before the drain was opened?
I have tried to solve by finding the rate which I think is 6 inches per every 2 minutes. Please help! Thankyou
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I am given a table that states:
TIme in Minutes Tub Has Been Draining, X: (3 then 5) Depth in Water in Tub in Inches, Y: (18 then 12)
----
You have two points relating time and depth: (3,18) and (5,12)
---
slope = (depth change)/(time change) = (18-12)/(3-5) = -6/2 = -3 inches per unit of time
---
Equation Form: depth = m(time)+b
Using (5,12) and m = -3, solve for "b":
12 = -3(5) + b
b = 27
----
Equation:
d = -3t + 27
-------------------
The question is:
How deep was the water before the drain was opened?
d(0) = --3*0 + 27
d(0) = 27 inches (depth of the water when time = zero)
==========================
Cheers,
Stan H.
===========
|
|
|
