SOLUTION: How do you solve for this inequality algebraically. (x+1)(x-2)(2^x) > 0

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Question 366837: How do you solve for this inequality algebraically.
(x+1)(x-2)(2^x) > 0
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B1%29%28x-2%29%282%5Ex%29+%3E+0+.
The factor 2%5Ex+%3E0 for all real values of x, and so we can just eliminate it from the inequality by dividing both sides by it. Hence we're actually solving
%28x%2B1%29%28x-2%29%3E+0+. The critical numbers are -1 and 2. Choosing test numbers x = -2, 0 and 3, we find out that the solution set is (-infinity, -1)U(2, infinity).