SOLUTION: f is a one-to-one function. The graph of f(x) contains the points (-16,-3).
Therefore the graph of f^-1(x) must contain the point
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-> SOLUTION: f is a one-to-one function. The graph of f(x) contains the points (-16,-3).
Therefore the graph of f^-1(x) must contain the point
(__,__)
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Question 366589: f is a one-to-one function. The graph of f(x) contains the points (-16,-3).
Therefore the graph of f^-1(x) must contain the point
(__,__) Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! In general, if f(x) has the inverse and the point (a,b) lies on the graph of f(x) (ie f(a)=b), then the point (b,a) lies on the graph of (since
So if the graph of f(x) contains (-16,-3), then contains the point (-3,-16)
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