SOLUTION: Find an angle such that 7 times the complement of the angle is 110 degrees greater than twice the supplement of the angle
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Question 366554: Find an angle such that 7 times the complement of the angle is 110 degrees greater than twice the supplement of the angle Answer by CharlesG2(834) (Show Source):
You can put this solution on YOUR website! Find an angle such that 7 times the complement of the angle is 110 degrees greater than twice the supplement of the angle
complementary angles add to 90 degrees
supplementary angles add to 180 degrees
let x be angle
let 90 - x be the angle's complement
let 180 - x be the angle's supplement
7(90 - x) = 2(180 - x) + 110
630 - 7x = 360 - 2x + 110
-7x + 2x = -630 + 360 + 110
-5x = -630 + 470
-5x = -160
x = 32, the angle is 32 degrees
its complement is 90 - 32 = 58 degrees
its supplement is 180 - 32 = 148 degrees
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