SOLUTION: an urn contains 10 red balls and 20 green balls, if four are drawn one at a time without replacement, what is the prob. that the sequence of colors will be RED, GREEN, RED, GREEN?

Algebra ->  Probability-and-statistics -> SOLUTION: an urn contains 10 red balls and 20 green balls, if four are drawn one at a time without replacement, what is the prob. that the sequence of colors will be RED, GREEN, RED, GREEN?      Log On


   



Question 366552: an urn contains 10 red balls and 20 green balls, if four are drawn one at a time without replacement, what is the prob. that the sequence of colors will be RED, GREEN, RED, GREEN?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi,
30 balls in the urn of which 10 are red and 20 are green
Drawing w/o replacement (after each draw, one less ball in the urn)
P(R,G,R,G) = 10/30 * 20/29 * 9/28 * 19/27