SOLUTION: factor completely c^5-4c^3-c^2+4

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Question 366509: factor completely
c^5-4c^3-c^2+4
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

c^5-4c^3-c^2+4

Testing: 2,-2, 1 are roots

by repeated division (or by using a polynomial calculator) One finds:

(c-2)(c + 2)(c-1)[c^2 + c + 1] 



c^2 + c + 1 has two imaginary roots

c+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ 

c+=+%28-1+%2B-+sqrt%28+-3+%29%29%2F%282%29+

c+=+%28-1+%2B-+i%2Asqrt%283%29%29%2F%282%29+