SOLUTION: write an equation in slope intercept form for th line that satisfies the following condition. passes through (10,16) perpendicular to the graph of 9x+12y=15
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-> SOLUTION: write an equation in slope intercept form for th line that satisfies the following condition. passes through (10,16) perpendicular to the graph of 9x+12y=15
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Question 366453: write an equation in slope intercept form for th line that satisfies the following condition. passes through (10,16) perpendicular to the graph of 9x+12y=15 Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! write an equation in slope intercept form for th line that satisfies the following condition. passes through (10,16) perpendicular to the graph of 9x+12y=15
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9x+12y=15
12y=-9x+15
/12
y=-9/12 x +15/9
y = -3/4 *x +5/3
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slope = -3/4
a line perpendicular to the given line will be 4/3
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point( 10,16)
(y-16)=4/3(x-10)
y-16 = 4/3 *x -40/3
y= 4/3*x-40/3+16
y=4x/3 +8/3
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m.ananth@hotmail.ca
